(x^2-4/6x+2)(x+7/x-2)

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Solution for (x^2-4/6x+2)(x+7/x-2) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(x^2-((4/6)*x)+2)*(x+7/x-2) = 0

(x^2+(-2/3)*x+2)*(x+7/x-2) = 0

(x^2-2/3*x+2)*(x+7*x^-1-2) = 0

x^2-2/3*x+2 = 0

x^2-2/3*x+2 = 0

DELTA = (-2/3)^2-(1*2*4)

DELTA = -68/9

DELTA < 0

1 = 0

x+7*x^-1-2 = 0

1*x^1+7*x^-1-2*x^0 = 0

(1*x^2-2*x^1+7*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2-2*x^1+7*x^0) = 0

x^1

x^2-2*x+7 = 0

x^2-2*x+7 = 0

DELTA = (-2)^2-(1*4*7)

DELTA = -24

DELTA < 0

x in { } 

1 = 0

1 = 0

x belongs to the empty set

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